mysql_fetch_row

(PHP 4, PHP 5, PECL mysql:1.0)

mysql_fetch_row — Get a result row as an enumerated array

Description

array mysql_fetch_row ( resource $result )

Returns a numerical array that corresponds to the fetched row and moves the internal data pointer ahead.

Parameters

result: The result resource that is being evaluated. This result comes from a call to mysql_query().

Return Values

Returns an numerical array of strings that corresponds to the fetched row, or FALSE if there are no more rows.

mysql_fetch_row() fetches one row of data from the result associated with the specified result identifier. The row is returned as an array. Each result column is stored in an array offset, starting at offset 0.

Examples

Example #1 Fetching one row with mysql_fetch_row()


<?php
$result = mysql_query("SELECT id,email FROM people WHERE id = '42'");
if (!$result) {
    echo 'Could not run query: ' . mysql_error();
    exit;
}
$row = mysql_fetch_row($result);

echo $row[0]; // 42
echo $row[1]; // the email value
?>

Notes

Note: This function sets NULL fields to the PHP NULL value.


sry :) note now fixed:



<?php

$esi=mysql_list_tables($db);$ris=mysql_fetch_row($esi);

//example: $db has >= 1 tabs

echo var_dump($ris);

//echoes only array(1). solution:

while($ris=mysql_fetch_row($esi)) echo $ris[0];

/*debug:

$ris=array("1st_tab"); ... $ris=array("n_tab");$ris=false;*/

while ($ris[]=mysql_fetch_row($esi));

//debug:$ris=array(array("1st_tab"), ... array("n_tab"));

echo $ris[n][0];//echo:"n_tab"

echo $ris[0][n];//echo:array | null

?>



hope it helps

ryhan_balboa at yahoo dot com
17-Nov-2007 01:23


The following are the basic codes to get a specific row from the mysql db into a $row variable:



 

$query = "SELECT * FROM table"; 

$result = mysql_query($query); 

$row = mysql_fetch_row($result);



And $row[0], $row[1] ... $row[n] are used to access those field values. 



Does anyone know how I can add a new field to $row, so that the field count increases from n to n+1?



I have tried treating $row like an array, and tried array_push function, but didn't work.



Thanks.

m dot s at programmers-online dot net
17-Nov-2005 05:56


The following function to read all data out of a mysql-resultset, is may be faster than Rafaels solution:



<?

function mysql_fetch_all($result) {

   while($row=mysql_fetch_array($result)) {

       $return[] = $row;

   }

   return $return;

}

?>

mysql at polyzing dot com
13-Jul-2003 06:05


It is probably worth pointing out that the array elements will actually be of type string, OR NULL if the field is null in the database.



Thus, either use a double equal comparison to look for empty or null



Or, use a triple equal comparison to be able to distinguish the two cases



e.g.



if ($field === '') echo "Empty, not NULL\n";



if ($field === NULL) echo "NULL\n";



if ($field == '') echo "Empty or NULL\n";

michael and then an at sign wassupy.com
08-Apr-2003 03:09


to print an array, simply use print_r(array name)



like this:

    $myrow = mysql_fetch_row($result);

echo "<pre>";

print_r($myrow);

echo "</pre>";



this will output the array in a readable form, with the index, too. Don't forget the 'pre' tags or the output will be on a single line.

a at simongrant dot org
06-Feb-2002 09:10


Maybe worth pointing out that all the fields returned by this (and other?) calls are returned with type string. This had me puzzled for quite some time.

add a note

mysql_field_flags

mysql_fetch_object

Last updated: Fri, 18 Jul 2008